Laboratory Exercise 10.1
We begin with a synthetic signal s distorted by stationary, additive, white, Gaussian noise N resulting in r = s + N where s[n] is a delayed impulse δ[nno] and the noise power density is No. The Wiener filter h to restore the signal s from r is given by Equation 10.22 which is specified in the frequency domain H and is repeated below:
(10.35) Missing Wiener equation
In this exercise we will examine how well this technique works. Use the slider control to adjust the signal-to-noise ratio. SNR. Use the playback buttons to listen to the original signal, the signal corrupted by noise, or the "restored" signal that results from Wiener filtering.
  1. Based upon the information given above, determine a simple expression for H(Ω).

  2. Starting from SNR = 1000:1, look at the output of the Wiener filter in the lower, right panel as the SNR is decreased. At what SNR is the signal no longer discernible from the noise?

  3. When comparing the result of the Wiener filtering to the noise signal displayed in the top, left panel, can the restoration filter make the signal visible after you would expect it to be buried (invisible) in the noise?

  4. After listening to the original signal, at what SNR can you no longer distinguish (hear) the signal embedded in the noise? Is the signal recognizable in the Wiener-filtered version? Is it visible in the panel in the bottom right?


SNR: N = ----- samples
= ----- ms
SNR = 1000:1

Original signal:           Signal + Noise:          
Signals s & N Log spectral densities Sss(2πf) & SNN(2πf)
Restored signal:          
Wiener filter HW (2πf) Wiener filter output with SNR = 1000:1